#include%26lt;math.h%26gt;
main()
{
float P,A,r,n;
Printf("Enter Amount : ");
scanf("%f",%26amp;A);
Printf("\nEnter Rate : ");
scanf("%r",%26amp;r);
Printf("\nEnter Time : ");
scanf("%f",%26amp;t);
P = A * pow(1+r,n);
printf(" \nValue of P = ",P);
}
What is the syntax for writing P=A(1+r)^n in 'C' language?
#include%26lt;stdio.h%26gt;
#include%26lt;conio.h%26gt;
void main()
{
int p,r,n,a,i;
clrscr();
printf("Input the value of r: ");
scanf("%d",%26amp;r);
printf("\n\nInput the value of n: ");
scanf("%d",%26amp;n);
printf("\n\nInput the value of A: ");
scanf("%d",%26amp;a);
p=1;
for(i=1;i%26lt;=n;i++)
p=p*(1+r);
p=p*a;
printf("\n\nA(1+r)^n=P=%d",p);
getch();
}
Reply:first include math.h file then use the following statement in the program
p=a*(pow((1+r),n))
Reply:the answer is 4
Reply:This may help you %26amp; reduce the size of your code
int Pow(int r, int n)
{
int temp;
int i;
int x = temp = r;
for(i = 1; i %26lt; n; i++)
{
temp = temp * x;
}
return temp;
}
call it this way from your main function
p = A * Pow((1+r), n);
Reply:P = A * pow(1+r, n);
Where 'pow' is in math.h
Reply:First include math.h
then using your logic write the equation in C syntax as:
P = A * pow(1+r, n);
pow is a power function it means the same that you want.
I hope you are satisfied.
Reply:copy and paste the following code in your editor and compile it.
P=A*pow((1+r),n).
Subscribe to:
Post Comments (Atom)
No comments:
Post a Comment